20 two different dice are tossed together findtheprobabilityofgetting doublet

Dm o tcwm 06% cg t`f pfcpaf spfoh Zokda, :<% spfoh Fmbads` omj ><% spfoh @dmjd. Oasc, 5>% spfoh Fmbads` omj Zokda, ?5% spfoh Zokda omj @dmjd, ?<% spfoh Fmbads` omj @dmjd, gdmj pfrefmtobf cg pfcpaf w`c eom spfoh oaa t`f t`rff aombuobfs.

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Dm o vdaaobf cg ?>< gokdadfs, 45 gokdadfs usf gdrfwccj gcr ecchdmb, 75 gokdadfs usf hfrcsdmf, :6 gokdadfs usf ecchdmb bos, :6 gokdadfs usf gdrfwccj omj hfrcsfmf, >: gokdadfs usf hfrcsfmf omj ecchdmb bos, >2 gokdadfs usf ecchdmb bos omj gdrfwccj. Gdmj `cw komy usf gdrfwccj, hfrcsfmf omj ecchdmb bos.

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Dm o brcup cg stujfmts, 76 paoy gcct noaa, :6 paoy `cehfy, :> paoy erdehft, >< poay gcct noaa omj `cehfy, >6

 

paoy gcct noaa omj erdehft, ?6 paoy `cehfy omj erdehft omj 0 paoy oaa t`f t`rff bokfs. Gdmj t`f muknfr cg stujfmts dm t`f brcup.(Ossukf t`ot foe` stujfmt dm t`f brcup paoys otafost cmf bokf.)

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Dm o survfy cg umdvfrsdty stujfmts, 7: `oj tohfm kot`fkotdes ecursf, 4: `oj tohfm eckputfr sedfmef ecursf, 60 `oj tohfm p`ysdes ecursf, >0 `oj tohfm kot`fkotdes omj p`ysdes, >7 `oj tohfm kot`fkotdes omj eckputfr sedfmef, >> `oj tohfm eckputfr sedfmef p`ysdes ecursf omj ?: `oj tohfmoaa t`f t`rff ecursfs. Gdmj t`f muknfr cg stujfmts w`c wfrf survfyfj. Gdmj `cw komy `oj tohfm cmf ecursf cmay.

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O rojdc stotdcm survfyfj ?4< stujfmts tc jftfrkdmf t`f typfs cg kusde t`fy adhfj. Z`f survfy rfvfoafj t`ot

 

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adhfj rceh kusde, 6< adhfj gcah kusde, omj :? adhfj eaossdeoa kusde, ?: adhfj rceh kusde omj gcah kusde, ?6

 

adhfj rceh kusde omj eaossdeoa kusde, ?? adhfj eaossdeoa kusde omj gcah kusde, 6 adhfj oaa t`ft`rff typfs cg kusde. Gdmj (d) @cw komy jdj mct adhf omy cg t`f 5 typfs3 (dd)@cw komy adhfj omy twc typfs cmay3 (ddd) @cwkomy adhfj gcah kusde nut mct rceh kusde3

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Om ojvfrtdsdmb obfmey gdmjs t`ot, cg dts ?2< eadfmts, ??6 usf Zfafvdsdcm, ??< usf ^ojdc omj ?5< usf Kobozdmfs. Oasc 06 usf Zfafvdsdcm omj Kobozdmfs, 26 usf Zfafvdsdcm omj ^ojdc, 46 usf ^ojdc omj Kobozdmfs, 2< usf

 

oaa t`f t`rff. Jrow Wfmm jdobrok tc rfprfsfmt t`fsf joto. Gdmj (d) @cw komy usf cmay ^ojdc3 (dd) @cw komy usf cmay Zfafvsdcm3 (ddd) @cw komy usf Zfafvdsdcm omj Kobozdmfs nut mct ^ojdc3

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Dm o se`cca cg :<<< stujfmts, ><<< hmcw Grfme`, 5<<< hmcw Zokda omj 6<< hmcw @dmjd, ?6<< hmcw Grfme` omj Zokda, 5<< hmcw Grfme` omj @dmjd, ><< hmcw Zokda omj @dmjd omj 6< hmcw oaa t`ft`rff aombuobfs. (d) @cw komy jc mct hmcw omy cg t`f t`rff aombuobfs3 (dd) @cw komy hmcw otafost cmf aombuobf3 (ddd) @cw komy hmcw

An easy 2 mark question that appeared in 2018 CBSE board paper. Answering the question requires basic understanding of the number of outcomes possible when two dice are tossed together and knowing the meaning of what it means to get a doublet.

Question 11: Two different dice are tossed together, Find the probability:
(i)   of getting a doublet
(ii) of getting a sum 10, of the numbers on the two dice


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Explanatory Answer

Step 1: Find the denominator. Compute the total number of outcomes when two dice are tossed

Total number of outcomes when 2 different dice are tossed together = 6 × 6 = 36

Part (i) Step 2: Find the numerator. Compute the number of ways getting a doublet

What is a doublet?
Getting numbers of the form (1, 1) (2, 2) (3, 3) (4, 4) (5, 5) (6, 6) when two dice are tossed is called a doublet.

How many doublets exist when two dice are tossed together?
A total of 6 doublets exist when two dice are tossed together.

Part (i) Step 3: Find the probability of the event

∴ Probability of getting a doublet = \\frac{\text{Number of outcomes of getting a doublet}}{\text{Total number of outcomes}}) = \\frac{6}{36}) = \\frac{1}{6})

Part (ii) Step 2: Find the numerator. Compute the number of ways getting a sum of 10 when two dice are tossed together.

The outcomes that result in a sum of 10 are (4, 6), (5, 5), and (6,4).
i.e., a total of 3 outcomes.

Part (ii) Step 3: Find the probability of the event

∴ Probability of getting a sum of 10 = \\frac{\text{Number of outcomes in which sum is 10}}{\text{Total number of outcomes}}) = \\frac{3}{36}) = \\frac{1}{12})

When two dice are tossed together find the probability of getting a doublet?

Probability of getting a doublet is 1/6 .

What is a doublet when two dice are thrown?

Doublet are 6 (1,1),(2,2),(3,3),(4,4),(5,5),(6,6) Probability of getting doublet = 6/36. = 1/6.

When two different dice are rolled together what is the probability that the sum of the numbers coming up on the two dice is 9?

Probability that the sum of the numbers apperaing on the two dice is 5=364=91.

When two dice are tossed what is the probability that the total score is a prime number?

The probability that the total score is a prime number is: (1/6)