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Hint: First we have to define what the terms we need to solve the problem are. Complete
step-by-step solution: Note: Since if two is multiplied we get the number as $2916 \times 2 = 5832$ and then we will separate like above we did we get; $3 \times 3 \times 3 \times 3 \times 3 \times 3 \times 2 \times 2 \times 2 = 5832$ hence all the twos are perfect square by three terms and all threes are perfect square by six terms thus the resultant. Question: Cheryl E. Algebra 9 months, 2 weeks ago Video Answer: Get the answer to your homework problem. Try Numerade free for 7 days We don’t have your requested question, but here is a suggested video that might help. Related Questionwhat is the smallest number by which 13500 should be multiplied so that the product is a perfect cube DiscussionYou must be signed in to discuss. Video TranscriptWhat is the smallest number by which 13500 should be added to make a perfect cube? As the given number is 13500 point, we have to find the smallest number we can to make a perfect cube. Factoring this is the first thing we will do. It is understood that to be a perfect cube, there will be a pair of factors by 3, so factor 13500 will be 2 raised to the power to multiply with 5 raised to the power 3 and 3 raised to the power 3. We have to add 2 to make them a perfect cube because there is not a perfect pair of 3 or 2. It will be 2 raised to the power 3, 5 raised to the power 3, and 3 raised to the power 3. It will be a perfect cube, so we can say that the smallest number, by which we have to add up, is 2. Solution: (i) 243 Prime factors of 243 = Here 3 do not appear in 3’s group. Therefore, 243 must be multiplied by 3 to make it a perfect cube. (ii) 256 Prime factors of 256 = 2\times2\times2\times2\times2\times2\times2\times2 Here one factor 2 is required to make a 3’s group. Therefore, 256 must be multiplied by 2 to make it a perfect cube. (iii) 72 Prime factors of 72 = 2\times2\times2\times3\times3 Here 3 does not appear in 3’s group. Therefore, 72 must be multiplied by 3 to make it a perfect cube. (iv) 675 Prime factors of 675 = 3\times3\times3\times5\times5 Here factor 5 does not appear in 3’s group. Therefore 675 must be multiplied by 3 to make it a perfect cube. (v) 100 Prime factors of 100 = 2\times2\times5\times5 Here factor 2 and 5 both do not appear in 3’s group. Therefore 100 must be multiplied by 2\times5= 10 to make it a perfect cube. What is the perfect cube of 500?The prime factorization of 500 is 2 × 2 × 5 × 5 × 5, hence, the cube root of 500 in its lowest radical form is expressed as 5 ∛4.
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Cube Root of 500.. What is the smallest number by which 500 may be multiplied to get a perfect square?500 is multiplied by 5 to get a perfect square .
What is the smallest number that can be multiplied by 500?The smallest natural will be 250 that can be multiplied with 500 to make it perfect cube.
IS 500 a perfect cube state with reason?triples. ∴ 500 is not a perfect cube.
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