How many 3-digit number can be formed using 1,2,3 or 4 if each digit can only be used once

distinct 3 digit number are formed using only the digits 1 2 3 4 with each digit used at most one in each number that the sum of all possible number so formed is now see in this question we need to form of three digit number out of this phone numbers and calculate the sum of all the digits form no see we have four numbers which is 1 2 3 and 4 and we need to form a three digit number out of this number now let us consider that this is the three digit number this is the street number 9 see for the first place we have four choices out of this phone numbers for second place we have we will have three choices and for third place will have two choices therefore in to conform 24243 Jeet number out of this using this phone number now she now let us consider that this is a particular case

Metallica concert year if it is 4 then we will have this place have three choices and this place have two choices their four digit ending with 4 is 6 similar Samsung Apple with 32 and ones digit ending with 4 or 6 digit ending with 36 and 2 and 1 therefore we can find the sum of unit place unit place will be some of unit place will be 4 + 3 + 2 + 1 into now this is equal to 16 some of the unit digit is 16 now sending will happen with this second digit and third digit therefore we will have zero sum at the end of this song will have zero taking 6 carry 60 + 6 will be 66 therefore six-year taking 6 carry this

60 60 plus 66 will be 66 this will be the sum of all the digits which is option A therefore option is our correct answer

In mathematics, permutation is known as the process of arranging a set in which all the members of a set are arranged into some series or order. The process of permuting is known as the rearranging of its components if the set is already arranged. Permutations take place, in more or less important ways, in almost every area of mathematics. They frequently appear when different commands on certain finite sets are considered.

What is a Combination?

A combination is an act of choosing items from a group, such that (not like permutation) the order of choice does not matter. In smaller cases, it is possible to count the number of combinations. Combination refers to the union of n things taken k at a time without repetition. In combination, you can select the items in any order. To those combinations in which re-occurrence is allowed, the terms k-selection or k-combination with replication are frequently used.

Permutation Formula

In permutation r things are selected from a set of n things without any replacement. In this order of selection matter.

nPr = (n!) / (n-r)!

Here,

n = set size, the total number of items in the set

r = subset size , the number of items to be selected from the set

Combination Formula

In combination r things are selected from a set of n things and where the order of selection does not matter.

nCr = n!/(n−r)!r!

Here, 

n = Number of items in set

r = Number of items selected from the set

How many 3-digit even numbers can be formed by using the digits 1,2,3,4, and 5?

Solution:

If repetition is allowed  

A three digit even number is to be formed from given 5 digits 1,2,3,4,5.

Ones place can be filled by 2 or 4 since the number is to be even. So, there are 2 ways to fill ones place.

Since, repetition is allowed , so tens place can be filled by 5 ways.

Likewise, hundreds place can also be filled by 5 ways.

So, number of ways in which three digit even numbers can be formed is 5 × 5 × 2 = 50

If repetition is not allowed

A three digit even number is to be formed from given 5 digits 1,2,3,4,5.

Ones place can be filled by 2 or 4 since the number is to be even. So, there are 2 ways to fill ones place.

Since, repetition is not allowed, so tens place can be filled by 4 ways.

Similarly, hundreds place can be filled by 3 ways.

So, number of ways in which three digit even numbers can be formed is 2 × 4 × 3 = 24

Similar Questions

Question 1: How many 3 digit odd numbers can be formed by using the digits 1,2,3,4 and 5?

Solution:

If repetition is allowed  

A three digit odd number is to be formed from given 5 digits 1,2,3,4,5.

Ones place can be filled by 1, 3 or 5 since the number is to be odd. So,

there are 3 ways to fill ones place.

Since, repetition is allowed , so tens place can be filled by 5 ways.

Similarly, hundreds place can also be filled by 5 ways.

So, number of ways in which three digit odd numbers can be formed is 5×5×3=75

If repetition is not allowed

A three digit odd number is to be formed from given 5 digits 1,2,3,4,5.

Since, for the number is to be odd , so ones place can be filled by 1, 3 or 5. So,

there are 3 ways to fill ones place.

Since, repetition is not allowed , so tens place can  be filled by 4 ways.

Similarly, hundreds place can  be filled by 3 ways.

So, number of ways in which three digit odd numbers can be formed is 3×4×3 =36

Question 2: How many 4 digit even numbers can be formed by using the digits 1,2,3,4 and 5?

Solution:

If repetition is allowed  

A four digit even number is to be formed from given 5 digits 1,2,3,4,5.

Since, for the number is to be even, so ones place can be filled by 2 or 4. So, there

are 2 ways to fill ones place.

Since, repetition is allowed, so tens place can be filled by 5 ways.

Similarly, hundreds place can also be filled by 5 ways.

Similarly, thousandth place can also be filled by 5 ways

So, number of ways in which four digit even numbers can be formed is 5 × 5 × 5 × 2 = 250

If repetition is not allowed

A four digit even number is to be formed from given 5 digits 1,2,3,4,5.

Since, for the number is to be even, so ones place can be filled by 2 or 4. So,

there are 2 ways to fill ones place.

Since, repetition is not allowed, so tens place can be filled by 4 ways.

Similarly, hundreds place can be filled by 3 ways.

Similarly, thousandth place can be filled by 2 ways

So, number of ways in which four digit even numbers can be formed is 2 × 4 × 3 × 2 = 48

How many 3

Thus, The total number of 3-digit numbers that can be formed = 5×4×3 = 60.

How many 3

∴ Total number of 3-digit numbers = 3×4×5=60.

How many numbers of 3 digits can be formed with the digits 1,2 3 4 and 5 without any repetition of digits?

so 60(ans.)