Which loop should you use when you want to display the odd numbers between 1 and 100?

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Given starting and endpoints, write a Python program to print all odd numbers in that given range. 

Example:

Input: start = 4, end = 15
Output: 5, 7, 9, 11, 13, 15

Input: start = 3, end = 11
Output: 3, 5, 7, 9, 11

Example #1: Print all odd numbers from the given list using for loop 

1. Define the start and end limit of the range.
2. Iterate from start till the range in the list using for loop and 
3. check if num % 2 != 0. 
4. If the condition satisfies, then only print the number. 

Python3

start, end = 4, 19

for num in range(start, end + 1):

    if num % 2 != 0:

        print(num, end = " ")

Output:

5 7 9 11 13 15 17 19 

  Example #2: Taking range limit from user input 

Python3

start = int(input("Enter the start of range:"))

end = int(input("Enter the end of range:"))

for num in range(start, end + 1):

    if num % 2 != 0:

        print(num)

Output:

Enter the start of range: 3
Enter the end of range: 7
3
5
7

Example #3: Taking range limit from user input or with static inputs to reduce code execution time and to increase code performance.

Python3

start = 5

end = 20

if start % 2 != 0:

    for num in range(start, end + 1, 2):

        print(num, end=" ")

else:

    for num in range(start+1, end + 1, 2):

        print(num, end=" ")

Output

5 7 9 11 13 15 17 19 

Example #4: Taking range limit from user input 

Python3

start = int(input("Enter the start of range: "))

end = int(input("Enter the end of range: "))

even_list = range(start, end + 1)[start%2::2]

for num in even_list:

    print(num, end = " ")

Enter the start of range: 3
Enter the end of range: 11
3 5 7 9 11 

Method: Using the lambda function

Python3

a=3;b=11

li=[]

for i in range(a,b+1):

    li.append(i)

odd_num = list(filter(lambda x: (x%2!=0),li)) 

print(odd_num)

Method: Using recursion 

Python3

def odd(num1,num2):

    if num1>num2:

        return

    print(num1+1,end=" ")

    return odd(num1+2,num2)

num1=4;num2=15

odd(num1,num2)

Method: Using list comprehension

Python3

x = [i for i in range(4,15+1) if i%2!=0]

print(*x)

Method: Using the enumerate function 

Python3

a=4;b=15;l=[]

for i in range(a,b+1):

  l.append(i)

print([a for j,a in enumerate(l) if a%2!=0])

Output

[5, 7, 9, 11, 13, 15]

Method: Using pass 

Python3

a=4;b=15

for i in range(a,b+1):

  if i%2==0:

    pass

  else:

    print(i,end=" ")

Method: Using filter method:

Python3

a=4;

b=15;

l= filter(lambda a : a%2 , range(a, b+1))

print(*l)

Output:

5 7 9 11 13 15